利用ASP发送和接收XML数据的处理方法
2018-09-06 12:12
request.asp
dim Https
set Https=server.createobject(MSXML2.XMLHTTP)
定义一个XMLHTTP对像
Https.open POST,
Https.send echo
123456 987654
11111 22222
if Https.readystate=4 then
response.write 提交成功
readstate读取状态为4则成功，继续后面的，不成功当然就不用继续处理了
dim objstream
set objstream = Server.CreateObject(adodb.stream)
定义一个stream，因为读过来的直接拿出来是乱码的，所以得处理一下
objstream.Type = 1
objstream.Mode =3
objstream.Open
objstream.Write Https.responseBody
objstream.Position = 0
objstream.Type = 2
objstream.Charset = GB2312
html = objstream.ReadText
转好码，就放到html里，好关闭这些对像
objstream.Close
set objstream = nothing
set https=nothing
end if
response.write html
response.asp
创建DOMDocument对象
Set xml = Server.CreateObject (msxml2.DOMDocument)
xml.async = False
装载POST数据
xml.Load Request
If xml.parseError.errorCode <> 0 Then
response.write 不能正确接收数据 & Description: & xml.parseError.reason & ＜br＞Line: & xml.parseError.Line
End If
set blogchild=xml.getElementsByTagName(misc_command)
the_text=blogchild.item(0).childnodes(1).text
the_text=blogchild.item(0).text
for i=0 to blogchild.length-1
response.write the_text
利用这种方法，ASP里调用Servlet或Web Service都是很轻松的！