HihoCoder1336 Matrix Sum(树状数组)

2021-07-20 03:07

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HihoCoder1336 Matrix Sum

描述

You are given an N × N matrix. At the beginning every element is 0. Write a program supporting 2 operations:

\1. Add x y value: Add value to the element Axy. (Subscripts starts from 0

\2. Sum x1 y1 x2 y2: Return the sum of every element Axy for x1 ≤ x ≤ x2, y1 ≤ y ≤ y2.

输入

The first line contains 2 integers N and M, the size of the matrix and the number of operations.

Each of the following M line contains an operation.

1 ≤ N ≤ 1000, 1 ≤ M ≤ 100000

For each Add operation: 0 ≤ x

For each Sum operation: 0 ≤ x1 ≤ x2

输出

For each Sum operation output a non-negative number denoting the sum modulo 109+7.

样例输入

5 8
Add 0 0 1
Sum 0 0 1 1
Add 1 1 1
Sum 0 0 1 1
Add 2 2 1
Add 3 3 1
Add 4 4 -1
Sum 0 0 4 4 

样例输出

1
2
3 

题解

题意

查询、修改二维数组中的相关值。

思路

二维树状数组维护所有操作,二维树状数组的相关操作与一维几乎完全相同。

代码

#pragma comment(linker, "/STACK:1024000000,1024000000")
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
using namespace std;
typedef long long ll;
const double PI = acos(-1.0);
const double eps = 1e-6;
const int INF = 0x3f3f3f3f;

#define REP(i,n) for(int i=0;i=1;i-=lowbit(i)){
        for(int j=y;j>=1;j-=lowbit(j)){
            ans += A[i][j];
            ans%=MOD;
        }
    }
    return ans;
}

int add(int x,int y,int val){
    for(int i=x;i

HihoCoder1336 Matrix Sum(树状数组)

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原文地址:https://www.cnblogs.com/caomingpei/p/9520198.html


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