C#跳过工作日，计算几个工作日之后到期的方法

标签：returns   date   turn   second   lap   type   ddd   web   switch   需求：消费者投诉企业，企业在2个工作日之内做出应答。   分析：1.工作日要刨去周末和法定节假日，而且每年的节假日不一样。 2.消费者可以在任意时间发起投诉，如果在非工作日发起了投诉，那么计算时间应该从工作日开始计算，就要刨去当日的时和分。   以下是代码： public class HolidayHelper { /// /// 判断法定工作日 /// /// 时间 /// 0上班，1不需要上班的周末（也包括节假日），2法定节假日 public static int IsHolidayOrWeek(DateTime dt) { //特殊的周末（周末却上班） string[] specalWeek2009 = { "0104", "0124", "0201", "0531", "0927", "1010" }; string[] specalWeek2010 = { "0220", "0221", "0612", "0613", "0919", "0925", "0926", "1009" }; string[] specalWeek2011 = { "0130", "0212", "0402", "1008", "1009" }; string[] specalWeek2012 = { "0129", "0331", "0401", "0428", "0929" }; string[] specalWeek2013 = { "0105", "0106", "0216", "0217", "0407", "0427", "0428", "0608", "0609", "0922", "0929", "1012" }; string[] specalWeek2014 = { "0126", "0208", "0504", "0928", "1011" }; string[] specalWeek2015 = { "0104", "0215", "0228", "0906", "1010" }; string[] specalWeek2016 = { "0206", "0214", "0612", "0918", "1008", "1009" }; string[] specalWeek2017 = { "0122", "0204", "0401", "0527", "0930" }; //法定假日 string[] holiday2009 = { "0101", "0102", "0103", "0125", "0126", "0127", "0128", "0129", "0130", "0131", "0404", "0405", "0406", "0501", "0502", "0503", "0528", "0529", "0530", "1001", "1002", "1003", "1004", "1005", "1006", "1007", "1008", }; string[] holiday2010 = { "0101", "0102", "0103", "0213", "0214", "0215", "0216", "0217", "0218", "0219", "0403", "0404", "0405", "0501", "0502", "0503", "0614", "0615", "0616", "0922", "0923", "0924", "1001", "1002", "1003", "1004", "1005", "1006", "1007" }; string[] holiday2011 = { "0101", "0102", "0103", "0202", "0203", "0204", "0205", "0206", "0207", "0208", "0403", "0404", "0405", "0430", "0501", "0502", "0604", "0605", "0606", "0910", "0911", "0912", "1001", "1002", "1003", "1004", "1005", "1006", "1007", }; string[] holiday2012 = { "0101", "0102", "0103", "0122", "0123", "0124", "0125", "0126", "0127", "0128", "0402", "0403", "0404", "0429", "0430", "0501", "0622", "0623", "0624", "0930", "1001", "1002", "1003", "1004", "1005", "1006", "1007", }; string[] holiday2013 = { "0101", "0102", "0103", "0209", "0210", "0211", "0212", "0213", "0214", "0215", "0404", "0405", "0406", "0429", "0430", "0501", "0610", "0611", "0612", "0919", "0920", "0921", "1001", "1002", "1003", "1004", "1005", "1006", "1007", }; string[] holiday2014 = { "0101", "0131", "0201", "0202", "0203", "0204", "0205", "0206", "0405", "0406", "0407", "0501", "0502", "0503", "0602", "0908", "1001", "1002", "1003", "1004", "1005", "1006", "1007", }; string[] holiday2015 = { "0101", "0102", "0103", "0218", "0219", "0220", "0221", "0222", "0223", "0224", "0404", "0405", "0406", "0501", "0502", "0503", "0620", "0621", "0622", "0903", "0904", "0905", "0927", "1001", "1002", "1003", "1004", "1005", "1006", "1007", }; string[] holiday2016 = { "0101", "0207", "0208", "0209", "0210", "0211", "0212", "0213", "0404", "0501", "0502", "0609", "0610", "0611", "0915", "0916", "0917", "1001", "1002", "1003", "1004", "1005", "1006", "1007", }; string[] holiday2017 = { "0101", "0102", "0127", "0128", "0129", "0130", "0131", "0201", "0202", "0403", "0404", "0501", "0529", "0530", "1001", "1002", "1003", "1004", "1005", "1006", }; bool isHoildayOrWeek = false; //取年 string weekYear = dt.Year.ToString(); //取月日 string[] weekDate = { dt.ToString("MMdd") }; //判断周末 if ((int)dt.DayOfWeek == 0 || (int)dt.DayOfWeek == 6) { //周末是否需要上班 switch (weekYear) { case "2009": isHoildayOrWeek = specalWeek2009.Intersect(weekDate).Count() == 0; break; case "2010": isHoildayOrWeek = specalWeek2010.Intersect(weekDate).Count() == 0; break; case "2011": isHoildayOrWeek = specalWeek2011.Intersect(weekDate).Count() == 0; break; case "2012": isHoildayOrWeek = specalWeek2012.Intersect(weekDate).Count() == 0; break; case "2013": isHoildayOrWeek = specalWeek2013.Intersect(weekDate).Count() == 0; break; case "2014": isHoildayOrWeek = specalWeek2014.Intersect(weekDate).Count() == 0; break; case "2015": isHoildayOrWeek = specalWeek2015.Intersect(weekDate).Count() == 0; break; case "2016": isHoildayOrWeek = specalWeek2016.Intersect(weekDate).Count() == 0; break; case "2017": isHoildayOrWeek = specalWeek2017.Intersect(weekDate).Count() == 0; break; } } if (isHoildayOrWeek) { return 1; } //判断法定节假日 switch (weekYear) { case "2009": isHoildayOrWeek = holiday2009.Intersect(weekDate).Count() > 0; break; case "2010": isHoildayOrWeek = holiday2010.Intersect(weekDate).Count() > 0; break; case "2011": isHoildayOrWeek = holiday2011.Intersect(weekDate).Count() > 0; break; case "2012": isHoildayOrWeek = holiday2012.Intersect(weekDate).Count() > 0; break; case "2013": isHoildayOrWeek = holiday2013.Intersect(weekDate).Count() > 0; break; case "2014": isHoildayOrWeek = holiday2014.Intersect(weekDate).Count() > 0; break; case "2015": isHoildayOrWeek = holiday2015.Intersect(weekDate).Count() > 0; break; case "2016": isHoildayOrWeek = holiday2016.Intersect(weekDate).Count() > 0; break; case "2017": isHoildayOrWeek = holiday2017.Intersect(weekDate).Count() > 0; break; } if (isHoildayOrWeek) { return 2; } return 0; } /// /// 工作日时间差 /// /// 几个工作日后 /// 延迟毫秒数 public static double GetDelpyTime(int days) { int sign = 0; for (int i = 0; i 0) { //非工作日发起的投诉，要抹掉小时和分钟 sign = 1; } if (IsHolidayOrWeek(DateTime.Now.AddDays(i)) > 0) { days = days + 1; }; } TimeSpan ts = new TimeSpan(); if (sign == 1) { ts = (DateTime.Now.AddDays(days) - DateTime.Now.AddHours(DateTime.Now.Hour).AddMinutes(DateTime.Now.Minute)); } else { ts = DateTime.Now.AddDays(days) - DateTime.Now; } return ts.TotalMilliseconds; } } View Code   谢谢大家。   打赏随意： C#跳过工作日，计算几个工作日之后到期的方法标签：returns   date   turn   second   lap   type   ddd   web   switch   原文地址：http://www.cnblogs.com/bzmy/p/7500837.html