Golang如何实现任意进制转换的方法示例

　　前言

　　最近因为工作的需要，需要写个短链服务，用到了10->62进制，网上找了一个，可以转换最多76位进制的博客，现在分享出来，下面话不多说了，来一起看看详细的介绍吧。

　　压缩数据用，无损压缩

　　示例代码：

　　 package main import ( fmt math strconv strings ) var tenToAny map[int]string = map[int]string{0: 0, 1: 1, 2: 2, 3: 3, 4: 4, 5: 5, 6: 6, 7: 7, 8: 8, 9: 9, 10: a, 11: b, 12: c, 13: d, 14: e, 15: f, 16: g, 17: h, 18: i, 19: j, 20: k, 21: l, 22: m, 23: n, 24: o, 25: p, 26: q, 27: r, 28: s, 29: t, 30: u, 31: v, 32: w, 33: x, 34: y, 35: z, 36: :, 37: ;, 38: <, 39: =, 40: >, 41: ?, 42: @, 43: [, 44: ], 45: ^, 46: _, 47: {, 48: , 49: }, 50: A, 51: B, 52: C, 53: D, 54: E, 55: F, 56: G, 57: H, 58: I, 59: J, 60: K, 61: L, 62: M, 63: N, 64: O, 65: P, 66: Q, 67: R, 68: S, 69: T, 70: U, 71: V, 72: W, 73: X, 74: Y, 75: Z} func main() { fmt.Println(decimalToAny(9999, 76)) fmt.Println(anyToDecimal(1F[, 76)) } // 10进制转任意进制 func decimalToAny(num, n int) string { new_num_str := var remainder int var remainder_string string for num != 0 { remainder = num % n if 76 > remainder && remainder > 9 { remainder_string = tenToAny[remainder] } else { remainder_string = strconv.Itoa(remainder) } new_num_str = remainder_string + new_num_str num = num / n } return new_num_str } // map根据value找key func findkey(in string) int { result := -1 for k, v := range tenToAny { if in == v { result = k } } return result } // 任意进制转10进制 func anyToDecimal(num string, n int) int { var new_num float64 new_num = 0.0 nNum := len(strings.Split(num, )) - 1 for _, value := range strings.Split(num, ) { tmp := float64(findkey(value)) if tmp != -1 { new_num = new_num + tmp*math.Pow(float64(n), float64(nNum)) nNum = nNum - 1 } else { break } } return int(new_num) }

　　总结

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