python监控网站运行异常并发送邮件的方法

本文实例讲述了python监控网站运行异常并发送邮件的方法。分享给大家供大家参考。具体如下：

这是一个简单的python开发的监控程序，当指定网页状态不正常是通过smtp发送通知邮件

复制代码 代码如下:#!/usr/bin/env python
# -*- coding: UTF-8 -*-
#author libertyspy
import socket
import smtplib
import urllib
mail_options = {
port:25, #端口
pwd:hacker, #发送人的密码
send_to:sniper@qq.com, #收件者
}
msg_options={
user:hacker, #短信平台的用户名
pwd:74110, #短信平台的密码
phone:12345678910, #需要发短信的电话号码
}
test_host =
def url_request(host,port=80):
try:
response = urllib.urlopen(host)
response_code = response.getcode()
if 200 != response_code:
return response_code
else:
return True
except IOError,e:
return False
def send_message(msg,host,status):
send_msg=服务器:%s挂了！状态码：%s % (host,status)
request_api=
% (msg[user],msg[pwd],msg[phone],send_msg)
return url_request(request_api)
def send_email(mail,host,status):
smtp = smtplib.SMTP()
smtp.connect(mail[server], mail[port])
smtp.login(mail[user],mail[pwd])
msg=From:%s\rTo:%s\rSubject:服务器: %s 挂了 !状态码:%s\r\n \
% (mail[user],mail[send_to],host,status)
smtp.sendmail(mail[user],mail[send_to], msg)
smtp.quit()

def check_status(host,port=80):
s = socket.socket()
ret_msg = []
try:
s.connect((host,port))
return True
except socket.error,e:
return False

if __name__==__main__:
status = url_request(test_host)
if status is not True and status is not None:
send_email(mail_options,test_host,status)
send_message(msg_options,test_host,status)
else:
pass

希望本文所述对大家的Python程序设计有所帮助。