LeetCode-Sliding Window Maximum
2021-03-31 17:27
标签:amp rom pos size 移除 linear last xsl solution 大概思路是用双向队列保存数字的下标,遍历整个数组,如果此时队列的首元素是i - k的话,表示此时窗口向右移了一步,则移除队首元素。然后比较队尾元素和将要进来的值,如果小的话就都移除,然后此时我们把队首元素加入结果中即可 LeetCode-Sliding Window Maximum 标签:amp rom pos size 移除 linear last xsl solution 原文地址:https://www.cnblogs.com/incrediblechangshuo/p/9252042.htmlGiven an array nums, there is a sliding window of size k which is moving from the very left of the array to the very right. You can only see the k numbers in the window. Each time the sliding window moves right by one position. Return the max sliding window.
Example:
Input: nums = [1,3,-1,-3,5,3,6,7], and k = 3
Output: [3,3,5,5,6,7]
Explanation:
Window position Max
--------------- -----
[1 3 -1] -3 5 3 6 7 3
1 [3 -1 -3] 5 3 6 7 3
1 3 [-1 -3 5] 3 6 7 5
1 3 -1 [-3 5 3] 6 7 5
1 3 -1 -3 [5 3 6] 7 6
1 3 -1 -3 5 [3 6 7] 7
Note:
You may assume k is always valid, 1 ≤ k ≤ input array‘s size for non-empty array.
Follow up:
Could you solve it in linear time?
class Solution {
public int[] maxSlidingWindow(int[] nums, int k) {
if(nums == null || nums.length == 0 || k ){
return new int[0];
}
int[] res = new int[nums.length-k+1];
Deque
文章标题:LeetCode-Sliding Window Maximum
文章链接:http://soscw.com/essay/70554.html