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2021-04-13 18:26
标签：tor 单表 java group rgs count 合并 lists 测试 话不多说，直接上代码，请朋友们自行测试~ public class Gamer47 { public static void main(String[] args) { //将List变成一个map mergeListmapToOnemap(null); //将两个List合并成一个List，“name”为map的key mergeTwoListmapToOneListmap(null,null,"name"); //对List分组统计 summaryGroup(); } /** * 对List 进行分组合并，按某个相同的key进行合并，并sum某个key， * 类似单表group by 功能 */ public static void summaryGroup(){ Map m1=new HashMap(); Map m11=new HashMap(); Map m12=new HashMap(); List> list =new ArrayList(); List> result =new ArrayList(); m1.put("aa", 11); m1.put("bb", "xm"); m1.put("cc", 122); m1.put("dd", 122); m11.put("aa", 12); m11.put("bb","xm"); m11.put("cc", 10); m11.put("dd", 122); m12.put("aa", 13); m12.put("bb", "zs"); m12.put("cc", 31); m12.put("dd", 122); list.add(m1); list.add(m11); list.add(m12); //按bb进行分组统计 Map>> glist = list.stream().collect(Collectors.groupingBy(e -> e.get("bb").toString())); glist.forEach((k,slist)->{ Map nmap=new HashMap(); IntSummaryStatistics sumcc = slist.stream().collect(Collectors.summarizingInt(e->Integer.valueOf(e.get("cc").toString()))); nmap.put("aa", slist.get(0).get("dd")); nmap.put("bb", slist.get(0).get("dd")); nmap.put("cc", sumcc.getSum());//求和 nmap.put("counts", slist.size());//计算 nmap.put("dd", slist.get(0).get("dd")); result.add(nmap); }); System.out.println("--------summaryGroup-------------"); result.forEach(x->{ System.out.println(x); }); } /** * list的中map合并为一个map,即List 转为Map newMap, * newMap中包含了list中每个map的key与value */ public static void mergeListmapToOnemap(List listmap){ Map h1 = new HashMap(); h1.put("12","fdsa"); h1.put("123","fdsa"); h1.put("124","fdsa"); h1.put("125","fdsa"); Map h2 = new HashMap(); h2.put("h12","fdsa"); h2.put("h123","fdsa"); h2.put("h124","fdsa"); h2.put("h125","fdsa"); Map h3 = new HashMap(); h3.put("h12","fdsa"); h3.put("h3123","fdsa"); h3.put("h3124","fdsa"); h3.put("h3125","fdsa"); List> lists = new ArrayList(); lists.add(h1); lists.add(h2); lists.add(h3); //用java 8 把lists里面的map合并成一个新的map: Map haNew = new HashMap(); // 包含了h1,h2,h3的内容 Map merged = lists.stream() .map(Map::entrySet) .flatMap(Set::stream) .distinct() .collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue)); Stream mlist = lists.stream().map(Map::entrySet); Stream fmlist = lists.stream() .map(Map::entrySet) .flatMap(Set::stream); System.out.println("merged="+merged); } /** * 两个list《map》中的map合并为一个list《map》,新的list中的每个map包含了之前的两个listmap的key */ public static void mergeTwoListmapToOneListmap(List list1,List list2,final String mergeKey){ List> lists = new ArrayList(); List> lists1 = new ArrayList(); List> lists2 = new ArrayList(); //--------------lists1-------------------- Map h1 = new HashMap(); h1.put("name","fdsa0"); h1.put("2","fdsa0"); h1.put("3","fdsa0"); h1.put("4","fdsa0"); Map h2 = new HashMap(); h2.put("name","fdsa00"); h2.put("2","fdsa00"); h2.put("3","fdsa00"); h2.put("4","fdsa00"); lists1.add(h1); lists1.add(h2); //--------------lists2-------------------- Map h3 = new HashMap(); h3.put("name","fdsa0"); h3.put("21","fdsa1"); h3.put("31","fdsa1"); h3.put("41","fdsa1"); Map h4 = new HashMap(); h4.put("name","fdsa00"); h4.put("21","fdsa2"); h4.put("31","fdsa2"); h4.put("41","fdsa2"); lists2.add(h3); lists2.add(h4); //测试 //mergeKey="name"; lists1.parallelStream().forEach(x->{ Map y2 = lists2.parallelStream().filter(y->y.get(mergeKey).toString().equals(x.get(mergeKey).toString())) .findFirst().get(); List> sublist = Arrays.asList(x,y2); Map merged = sublist.stream() .map(Map::entrySet) .flatMap(Set::stream) .distinct() .collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue)); lists.add(merged); }); System.out.println("----------list--mergetMap---------"); lists.forEach(x->{ System.out.println(x); }); } java8 Stream对List的分组合并操作 标签：tor 单表 java group rgs count 合并 lists 测试 原文地址：https://www.cnblogs.com/47Gamer/p/13340507.html
标签：tor 单表 java group rgs count 合并 lists 测试
话不多说，直接上代码，请朋友们自行测试~
public class Gamer47 { public static void main(String[] args) { //将List变成一个map mergeListmapToOnemap(null); //将两个List合并成一个List，“name”为map的key mergeTwoListmapToOneListmap(null,null,"name"); //对List分组统计 summaryGroup(); } /** * 对List 进行分组合并，按某个相同的key进行合并，并sum某个key， * 类似单表group by 功能 */ public static void summaryGroup(){ Map m1=new HashMap(); Map m11=new HashMap(); Map m12=new HashMap(); List> list =new ArrayList(); List> result =new ArrayList(); m1.put("aa", 11); m1.put("bb", "xm"); m1.put("cc", 122); m1.put("dd", 122); m11.put("aa", 12); m11.put("bb","xm"); m11.put("cc", 10); m11.put("dd", 122); m12.put("aa", 13); m12.put("bb", "zs"); m12.put("cc", 31); m12.put("dd", 122); list.add(m1); list.add(m11); list.add(m12); //按bb进行分组统计 Map>> glist = list.stream().collect(Collectors.groupingBy(e -> e.get("bb").toString())); glist.forEach((k,slist)->{ Map nmap=new HashMap(); IntSummaryStatistics sumcc = slist.stream().collect(Collectors.summarizingInt(e->Integer.valueOf(e.get("cc").toString()))); nmap.put("aa", slist.get(0).get("dd")); nmap.put("bb", slist.get(0).get("dd")); nmap.put("cc", sumcc.getSum());//求和 nmap.put("counts", slist.size());//计算 nmap.put("dd", slist.get(0).get("dd")); result.add(nmap); }); System.out.println("--------summaryGroup-------------"); result.forEach(x->{ System.out.println(x); }); } /** * list的中map合并为一个map,即List 转为Map newMap, * newMap中包含了list中每个map的key与value */ public static void mergeListmapToOnemap(List listmap){ Map h1 = new HashMap(); h1.put("12","fdsa"); h1.put("123","fdsa"); h1.put("124","fdsa"); h1.put("125","fdsa"); Map h2 = new HashMap(); h2.put("h12","fdsa"); h2.put("h123","fdsa"); h2.put("h124","fdsa"); h2.put("h125","fdsa"); Map h3 = new HashMap(); h3.put("h12","fdsa"); h3.put("h3123","fdsa"); h3.put("h3124","fdsa"); h3.put("h3125","fdsa"); List> lists = new ArrayList(); lists.add(h1); lists.add(h2); lists.add(h3); //用java 8 把lists里面的map合并成一个新的map: Map haNew = new HashMap(); // 包含了h1,h2,h3的内容 Map merged = lists.stream() .map(Map::entrySet) .flatMap(Set::stream) .distinct() .collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue)); Stream mlist = lists.stream().map(Map::entrySet); Stream fmlist = lists.stream() .map(Map::entrySet) .flatMap(Set::stream); System.out.println("merged="+merged); } /** * 两个list《map》中的map合并为一个list《map》,新的list中的每个map包含了之前的两个listmap的key */ public static void mergeTwoListmapToOneListmap(List list1,List list2,final String mergeKey){ List> lists = new ArrayList(); List> lists1 = new ArrayList(); List> lists2 = new ArrayList(); //--------------lists1-------------------- Map h1 = new HashMap(); h1.put("name","fdsa0"); h1.put("2","fdsa0"); h1.put("3","fdsa0"); h1.put("4","fdsa0"); Map h2 = new HashMap(); h2.put("name","fdsa00"); h2.put("2","fdsa00"); h2.put("3","fdsa00"); h2.put("4","fdsa00"); lists1.add(h1); lists1.add(h2); //--------------lists2-------------------- Map h3 = new HashMap(); h3.put("name","fdsa0"); h3.put("21","fdsa1"); h3.put("31","fdsa1"); h3.put("41","fdsa1"); Map h4 = new HashMap(); h4.put("name","fdsa00"); h4.put("21","fdsa2"); h4.put("31","fdsa2"); h4.put("41","fdsa2"); lists2.add(h3); lists2.add(h4); //测试 //mergeKey="name"; lists1.parallelStream().forEach(x->{ Map y2 = lists2.parallelStream().filter(y->y.get(mergeKey).toString().equals(x.get(mergeKey).toString())) .findFirst().get(); List> sublist = Arrays.asList(x,y2); Map merged = sublist.stream() .map(Map::entrySet) .flatMap(Set::stream) .distinct() .collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue)); lists.add(merged); }); System.out.println("----------list--mergetMap---------"); lists.forEach(x->{ System.out.println(x); }); }
java8 Stream对List的分组合并操作
原文地址：https://www.cnblogs.com/47Gamer/p/13340507.html
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