链表排序
标签:else spl print sizeof node tmp lse src tno
https://leetcode.com/problems/insertion-sort-list/description/
1、归并排序:
#include
#include "table.h"
using namespace std;
typedef long long int LL;
struct ListNode {
int val;
ListNode *next;
ListNode(int x) : val(x), next(NULL) {}
};
class Solution {
public:
ListNode* findMid(ListNode *head) {
if (head == NULL || head->next == NULL) return head;
ListNode *slow = head, *fast = head->next;
while (fast && fast->next) {
slow = slow->next;
fast = fast->next->next;
}
ListNode *tmp = slow->next;
slow->next = NULL;
return tmp;
}
ListNode* merge(ListNode* one, ListNode* two) {
ListNode *first = NULL;
if (one->val val) {
first = one;
one = one->next;
} else {
first = two;
two = two->next;
}
ListNode *ans = first;
while (one && two) {
if (one->val val) {
first->next = one;
one = one->next;
} else {
first->next = two;
two = two->next;
}
first = first->next;
}
while (one) {
first->next = one;
one = one->next;
first = first->next;
}
while (two) {
first->next = two;
two = two->next;
first = first->next;
}
return ans;
}
ListNode* guibin(ListNode* head) {
if (head == NULL || head->next == NULL) return head;
if (head->next->next == NULL) {
if (head->val > head->next->val) {
swap(head->val, head->next->val);
}
return head;
}
ListNode* mid = findMid(head);
ListNode* one = guibin(head);
ListNode* two = guibin(mid);
return merge(one, two);
}
ListNode* insertionSortList(ListNode* head) {
return guibin(head);
}
};
void work() {
int a[] = {4, 1, 2, 3, 5, 8};
int len = sizeof(a) / sizeof(a[0]);
ListNode* first = new ListNode(a[0]);
ListNode* tmp = first;
for (int i = 1; i i) {
first->next = new ListNode(a[i]);
first = first->next;
}
tmp = t.insertionSortList(tmp);
while (tmp) {
printf("%d\n", tmp->val);
tmp = tmp->next;
}
}
int main() {
work();
return 0;
}
View Code
链表排序
标签:else spl print sizeof node tmp lse src tno
原文地址:https://www.cnblogs.com/liuweimingcprogram/p/9649582.html
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文章标题:
链表排序
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