226. 翻转二叉树python

2021-06-29 08:03

阅读:735

标签:solution   roo   nod   rtt   tree   temp   ==   self   div   

翻转一棵二叉树。

示例:

输入:

     4
   /     2     7
 / \   / 1   3 6   9

输出:

4
   /     7     2
 / \   / 9   6 3   1
# Definition for a binary tree node.
# class TreeNode:
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None

class Solution:
    def invertTree(self, root):
        """
        :type root: TreeNode
        :rtype: TreeNode
        """
        if root == None:
            return root
        temp = root.left
        root.left = root.right
        root.right = temp
        
        self.invertTree(root.left)
        self.invertTree(root.right)
        
        return root

  

226. 翻转二叉树python

标签:solution   roo   nod   rtt   tree   temp   ==   self   div   

原文地址:https://www.cnblogs.com/zyjdbk/p/9646353.html

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