Python基础之深浅copy
2021-07-02 11:06
标签:import int 一致性 3.3 3.1 2.4 print 赋值 执行 对于赋值运算来说,lst1和lst2指向的是同一个内存地址,所以它们是一样的。 执行结果为: 执行结果为: 执行结果为: 对于浅copy来所,第一层创建的是新的内存地址,而从第二层开始,指向的都是同一个内存地址。
所以,对于第二层以及更深的层数来说,保持一致性。 执行结果为: 执行结果为: 执行结果为: 对于deepcopy来说,两个是完全独立的,改变任意一个的任何元素(无论多少层),另一个绝对不改变。 Python基础之深浅copy 标签:import int 一致性 3.3 3.1 2.4 print 赋值 执行 原文地址:https://www.cnblogs.com/yang-wei/p/9630540.html1. 赋值
lst1 = [1, 2, 3, ["a", "b", "c"]]
lst2 = lst1
lst1[0] = 11
print(lst1) #[11, 2, 3, [‘a‘, ‘b‘, ‘c‘]]
print(lst2) #[11, 2, 3, [‘a‘, ‘b‘, ‘c‘]]
lst1[3][0] = "d"
print(lst1) #[11, 2, 3, [‘d‘, ‘b‘, ‘c‘]]
print(lst2) #[11, 2, 3, [‘d‘, ‘b‘, ‘c‘]]
2. 浅copy
2.1 示例1
lst1 = [1, 2, 3, ["a", "b", "c"]]
lst2 = lst1.copy()
print(lst1, id(lst1))
print(lst2, id(lst2))
[1, 2, 3, [‘a‘, ‘b‘, ‘c‘]] 48285736
[1, 2, 3, [‘a‘, ‘b‘, ‘c‘]] 48285776
2.2 示例二
lst1 = [1, 2, 3, ["a", "b", "c"]]
lst2 = lst1.copy()
lst1[0] = 11
print(lst1, id(lst1))
print(lst2, id(lst2))
[11, 2, 3, [‘a‘, ‘b‘, ‘c‘]] 48285736
[1, 2, 3, [‘a‘, ‘b‘, ‘c‘]] 48285776
2.3 示例三
lst1 = [1, 2, 3, ["a", "b", "c"]]
lst2 = lst1.copy()
lst1[3][0] = "d"
print(lst1, id(lst1))
print(lst2, id(lst2))
[1, 2, 3, [‘d‘, ‘b‘, ‘c‘]] 48285536
[1, 2, 3, [‘d‘, ‘b‘, ‘c‘]] 48285736
2.4 总结
3. 深拷贝(deepcopy)
3.1 示例一
import copy
lst1 = [1, 2, 3, ["a", "b", "c"]]
lst2 = copy.deepcopy(lst1)
print(lst1, id(lst1))
print(lst2, id(lst2))
[1, 2, 3, [‘a‘, ‘b‘, ‘c‘]] 54249392
[1, 2, 3, [‘a‘, ‘b‘, ‘c‘]] 54249992
3.2 示例二
import copy
lst1 = [1, 2, 3, ["a", "b", "c"]]
lst2 = copy.deepcopy(lst1)
lst1[0] = 11
print(lst1, id(lst1))
print(lst2, id(lst2))
[11, 2, 3, [‘a‘, ‘b‘, ‘c‘]] 48678832
[1, 2, 3, [‘a‘, ‘b‘, ‘c‘]] 48679432
3.3 示例三
import copy
lst1 = [1, 2, 3, ["a", "b", "c"]]
lst2 = copy.deepcopy(lst1)
lst1[3][0] = "d"
print(lst1, id(lst1))
print(lst2, id(lst2))
[1, 2, 3, [‘d‘, ‘b‘, ‘c‘]] 46516144
[1, 2, 3, [‘a‘, ‘b‘, ‘c‘]] 46516744
3.4 总结