（ajaxfileupload）ajaxfileupload 上传时会出现连接重置的问题

 1 前台： 
 2 style type="text/css">
 3         .fileLink{position: relative;display: inline-block;background: #fff;border: 1px solid #0980D0;border-radius: 4px;padding: 2px 8px;margin-left:10px;margin-top:10px;overflow: hidden;color: #1E88C7;text-decoration: none;text-indent: 0;line-height: 20px;}
 4         .fileLink input {position: absolute;font-size: 100px;right: 0;top: 0;opacity: 0;}
 5         .fileLink:hover {background: #AADFFD;border-color: #78C3F3;cursor:pointer;color: #004974;text-decoration: none;}
 6     style>
 7 span class="fL fileLink" style="padding-left: 10px;">选择文件input type="file" id="uploadify" name="uploadify" value="上传数据" />span>
 8 script src="../../Plugins/jquery/jquery-1.7.2.min.js" type="text/javascript">script>
 9 script src="../../Plugins/ajaxfileupload.js" type="text/javascript">script>
10 
11 script>
12        $("#uploadify").on("change", function () {
13             //var file = $("#uploadify")[0].files[0];
14             $.ajaxFileUpload({
15                 url: ‘./ImportDynamic.ashx‘,
16                 fileElementId: ‘uploadify‘,
17                 dataType: ‘text‘,
18                 success: function (data, status) {
19                     alert(1);
20                 },
21                 error: function () { }
22             });
23         });
24 script>
25  
26 一般处理程序：
27             context.Response.ContentType = "text/plain";
28             var filePath = "uploadfile/xxx.xls";
29             filePath = context.Server.MapPath(filePath);
30             Import.GetCommonReportFile(filePath);
31             //context.Response.Write("返回文本数据，否则前台就会报如上错误");