分析轮子(六)- LinkedList.java

2021-07-02 17:04

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标签:soscw   cep   mic   dex   rac   ansi   image   实现   有一个   

注:玩的是JDK1.7版本

一:先上类的继承结构图

技术分享图片

二:再看一下他的底层实现数据结构

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三:然后从源码中找点好玩的东西

 1)双向链表的结构构成元素,头指针、尾指针、节点信息(前向指针、后向指针、节点信息)

    /**
     * Pointer to first node.
     * Invariant: (first == null && last == null) ||
     *            (first.prev == null && first.item != null)
     */
    transient Node first;

    /**
     * Pointer to last node.
     * Invariant: (first == null && last == null) ||
     *            (last.next == null && last.item != null)
     */
    transient Node last;
    private static class Node {
        E item;
        Node next;
        Node prev;

        Node(Node prev, E element, Node next) {
            this.item = element;
            this.next = next;
            this.prev = prev;
        }
    }

2)在链表尾部添加新节点,只需要改变链表尾指针的指针指向就可了所以,性能相对 ArrayList.java 的数组拷贝会好很多

    /**
     * Appends the specified element to the end of this list.
     *
     * 

This method is equivalent to {

@link #addLast}. * * @param e element to be appended to this list * @return {@code true} (as specified by {@link Collection#add}) */ public boolean add(E e) { linkLast(e); return true; }
    /**
     * Links e as last element.
     */
    void linkLast(E e) {
        final Node l = last;
        final Node newNode = new Node(l, e, null);
        last = newNode;
        if (l == null)
            first = newNode;
        else
            l.next = newNode;
        size++;
        modCount++;
    }

3)根据索引位置,获取节点,会遍历链表性能相对会差一些并且我们也能看到遍历的时候也有一个优化,通过索引位置和链表长度的一半比较,决定从头遍历还是从尾遍历,这样能通过减少遍历长度加快遍历速度的作用,不过当索引位置在中间的时候,就不好玩了,无论从头或从尾遍历性能不会比较差

    /**
     * Returns the element at the specified position in this list.
     *
     * @param index index of the element to return
     * @return the element at the specified position in this list
     * @throws IndexOutOfBoundsException {@inheritDoc}
     */
    public E get(int index) {
        checkElementIndex(index);
        return node(index).item;
    }
    /**
     * Returns the (non-null) Node at the specified element index.
     */
    Node node(int index) {
        // assert isElementIndex(index);

        if (index > 1)) {
            Node x = first;
            for (int i = 0; i )
                x = x.next;
            return x;
        } else {
            Node x = last;
            for (int i = size - 1; i > index; i--)
                x = x.prev;
            return x;
        }
    }

4)根据节点信息获取索引位置的方法,可以看到节点信息是允许为null的

    /**
     * Returns the index of the first occurrence of the specified element
     * in this list, or -1 if this list does not contain the element.
     * More formally, returns the lowest index {@code i} such that
     * (o==null ? get(i)==null : o.equals(get(i))),
     * or -1 if there is no such index.
     *
     * @param o element to search for
     * @return the index of the first occurrence of the specified element in
     *         this list, or -1 if this list does not contain the element
     */
    public int indexOf(Object o) {
        int index = 0;
        if (o == null) {
            for (Node x = first; x != null; x = x.next) {
                if (x.item == null)
                    return index;
                index++;
            }
        } else {
            for (Node x = first; x != null; x = x.next) {
                if (o.equals(x.item))
                    return index;
                index++;
            }
        }
        return -1;
    }

5)下面的三个方法,是根据索引位置,修改、删除索引位置的节点,都会遍历链表,所以,性能相对会差一些,ArrayListljava 是通过数组的索引位置直接操作的

    /**
     * Replaces the element at the specified position in this list with the
     * specified element.
     *
     * @param index index of the element to replace
     * @param element element to be stored at the specified position
     * @return the element previously at the specified position
     * @throws IndexOutOfBoundsException {@inheritDoc}
     */
    public E set(int index, E element) {
        checkElementIndex(index);
        Node x = node(index);
        E oldVal = x.item;
        x.item = element;
        return oldVal;
    }
    /**
     * Inserts the specified element at the specified position in this list.
     * Shifts the element currently at that position (if any) and any
     * subsequent elements to the right (adds one to their indices).
     *
     * @param index index at which the specified element is to be inserted
     * @param element element to be inserted
     * @throws IndexOutOfBoundsException {@inheritDoc}
     */
    public void add(int index, E element) {
        checkPositionIndex(index);

        if (index == size)
            linkLast(element);
        else
            linkBefore(element, node(index));
    }
    /**
     * Removes the element at the specified position in this list.  Shifts any
     * subsequent elements to the left (subtracts one from their indices).
     * Returns the element that was removed from the list.
     *
     * @param index the index of the element to be removed
     * @return the element previously at the specified position
     * @throws IndexOutOfBoundsException {@inheritDoc}
     */
    public E remove(int index) {
        checkElementIndex(index);
        return unlink(node(index));
    }

6)双向链表也可以当做双向队列使用

技术分享图片

分析轮子(六)- LinkedList.java

标签:soscw   cep   mic   dex   rac   ansi   image   实现   有一个   

原文地址:https://www.cnblogs.com/godtrue/p/9629535.html


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