多文件上传的例子
2018-09-07 12:30
多文件上传的例子 //upload_html.php---------------------------------------------------------------------------------------------
<HTML>
<HEAD>
<TITLE>上传文件</TITLE>
</HEAD>
<script>
function beforesubmit(forma)
{
var upfilea=forma.upfile.value;
var k=/ /g;
var indexnamea=indexnamea.replace(k,);
var upfilea=upfilea.replace(k,);
if(indexnamea==
upfilea==)
{
alert(目录名称或上传的目录不能为空!);
return false;
}
return true;
}
</script>
<BODY BGCOLOR=WHITE>
<BR>
<form name=form1 action=upload.php method=post enctype=\multipart/form-data\ >\n;
<table cellspacing=1 cellpadding=5 border=0 width=580 bgcolor=#C2E2F5>
<tr bgcolor=#E3F2FB align=center>
<td width=280 align=center height=30>上传的文件</td>
</tr>
<?
for($i=1;$i<8;$i++)
{
$upfile=upfile.strval($i);
echo <tr>\n;
echo <td bgcolor=#F5FBFE width=264><input type=file name=$upfile lengh=25></td>\n;
echo </tr>\n;
}
?>
<tr bgcolor=#E3F2FB>
<td colspan=2 height=1>
</td>
<td colspan=2 height=1>
<div align=center>
<input type=submit name=submit value=上传>
</div>
</td>
</table>
</form>
</body></html>
//-----------------------------------------------------------------------------------------------------------------------
//upload.php-------------------------------------------------------------------------------------------------------------
//upload_path:文件要上传到的目录路径
<?php
for($i=1;$i<8;$i++)
{
$upfile=upfile.strval($i);
if(chop($$indexname)!= and chop($$upfile)!=)
{
$upfilename=($upfile._name);
$filename=upload_path.$$upfilename;
$copyfile = copy($$upfile,$filename);
if (!$copyfile)
die(文件上传失败!);
$ls_file.=$$upfilename.\n;
$flag=1 ;
}
}
if($flag){
$ls_msg=文件\n.$ls_file.上传成功!;
}
else{
$ls_msg=无文件上传,请重新选择!;
}
echo <HTML>\n ;
echo <HEAD>\n ;
echo </HEAD>\n ;
echo <BODY >\n ;
echo $ls_msg.\n;
echo </BODY>\n ;
echo </HTML>\n ;
?>