将Excel导入DataGridView 中的"select * from [Sheet1$]"中[ ]里面表单名的动态获取
2020-11-16 00:19
标签：datagridview com class http blog code div img style java javascript Sheet1$是Excel默认的第一个表名，如果改动：select * from
[Sheet1$]"将查询失败，因此应根据选择自动获取excel表名： 将Excel导入DataGridView 中的"select * from [Sheet1$]"中[
]里面表单名的动态获取,搜素材,soscw.com 将Excel导入DataGridView 中的"select * from [Sheet1$]"中[
]里面表单名的动态获取 标签：datagridview com class http blog code div img style java javascript 原文地址：http://www.cnblogs.com/qiernonstop/p/3694925.html
1 OpenFileDialog ofd = new OpenFileDialog(); //选择文件路径
2 ofd.Title = "Excel文件";
3 ofd.FileName = "";
4 ofd.Filter = "Excel文件(*.xls)| *.xls";
5 string Path = ofd.FileName;
6 string tableName = "";
7
8 string strConn = "Provider=Microsoft.Jet.OLEDB.4.0;" + "Data Source=" + Path + ";" + "Extended Properties=Excel 8.0;";
9 OleDbConnection conn = new OleDbConnection(strConn);
10 conn.Open();
11 System.Data.DataTable sTable = conn.GetOleDbSchemaTable(System.Data.OleDb.OleDbSchemaGuid.Tables, null);
12 tableName = sTable.Rows[0][2].ToString().Trim();
13
14 for (int i = 0; i )
15 {
16 schemaTable.Rows[i][2].ToString().TrimStart(‘\‘‘).Trim(‘\‘‘, ‘$‘);
17 }
18
19 string strExcel = "select * from [" + tableName + "]";
20 OleDbDataAdapter myCommand = new OleDbDataAdapter(strExcel, strConn);
21 DataSet ds = new DataSet();
22 DataTable table1 = new DataTable();
23 myCommand.Fill(table1);
24 //==========最后绑定
25 dataGridView1.DataSource = table1;
文章标题：将Excel导入DataGridView 中的"select * from [Sheet1$]"中[ ]里面表单名的动态获取
文章链接：http://soscw.com/index.php/essay/21571.html