Python两数相加
2021-02-08 06:18
标签:node lis append efi 除了 end self lang sel 给出两个 非空 的链表用来表示两个非负的整数。其中,它们各自的位数是按照 逆序 的方式存储的,并且它们的每个节点只能存储 一位 数字。 如果,我们将这两个数相加起来,则会返回一个新的链表来表示它们的和。 您可以假设除了数字 0 之外,这两个数都不会以 0 开头。 示例: Python两数相加 标签:node lis append efi 除了 end self lang sel 原文地址:https://www.cnblogs.com/zyyhxbs/p/12771778.html两数相加
输入:(2 -> 4 -> 3) + (5 -> 6 -> 4)
输出:7 -> 0 -> 8
原因:342 + 465 = 807
思路一:
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
class Solution:
def addTwoNumbers(self, l1: ListNode, l2: ListNode) -> ListNode:
lst1 = []
while l1:
lst1.append(l1.val)
l1 = l1.next
lst2 = []
while l2:
lst2.append(l2.val)
l2 = l2.next
m, n = len(lst1), len(lst2)
if m 9:
num = num - 10
lst3.append(num)
if i == m - 1:
lst3.append(1)
else:
lst1[i + 1] += 1
else:
lst3.append(num)
node = ListNode(lst3[0])
cur = node
for i in lst3[1:]:
node_ = ListNode(i)
cur.next = node_
cur = node_
return node
思路二:
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
class Solution:
def addTwoNumbers(self, l1: ListNode, l2: ListNode) -> ListNode:
jin_wei = 0
head = cur = None
while l1 or l2:
l1_val = l1.val if l1 else 0
l2_val = l2.val if l2 else 0
l1 = l1.next if l1 else None
l2 = l2.next if l2 else None
num = l1_val + l2_val
if jin_wei == 1:
num += 1
jin_wei = 0
if num > 9:
num = num - 10
jin_wei = 1
if not head:
head = ListNode(num)
cur = head
else:
node = ListNode(num)
cur.next = node
cur = node
if jin_wei == 1:
cur.next = ListNode(1)
return head
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