2020计算机C语言

 1 #include 2 int num[100];
 3 int main()
 4 {
 5     int x;
 6     int cnt = 0; 
 7     scanf("%d", &x);
 8     while(x) {
 9         num[++cnt] = x % 10;
10         x = x / 10;
11     }
12     if(!cnt) printf("0\n");
13     else {
14         for(int i = cnt; i>=1; i--)
15             printf("%d\n", num[i]);
16     }
17     return 0; 
18 }

1 #include2 int main()
3 {
4     int x;
5     scanf("%d", &x);
6     printf("%c\n", x);
7     return 0;
8 }

#includeint main()
{
    int x; 
    scanf("%d",&x);
    printf("x=%d,x=%o,x=%x\n", x, x, x);
    return 0;
}
// -1
// x=-1,x=37777777777, x=ffffffff

#includeint main()
{
    int x, y, ans;
    char op;
    scanf("%d %c %d", &x, &op, &y);
    if(op==‘+‘)
        ans = x + y;
    else if(op==‘-‘)
        ans = x - y;
    else if(op==‘/‘)
        ans = x / y;
    else
        ans = x % y;
    printf("%d\n", ans);
    return 0;
}

#includeint fun(int x, char op, int y) {
    int ans;
    if(op==‘+‘)
        ans = x + y;
    else if(op==‘-‘)
        ans = x - y;
    else if(op==‘/‘)
        ans = x / y;
    else
        ans = x % y;
    return ans;
}
int main()
{
    int x, y;
    char op;
    scanf("%d %d %c",&x, &y, &op);
    if(op==‘/‘ && y==0)
        printf("Go to hell!\n");
    printf("%d\n", fun(x, op, y));
    return 0;
}

#includeint main()
{
    int op; 
    double d, ans;
    scanf("%d %lf", &op, &d);
    if(op==1) {
        ans = (d - 32) * 5 / 9;
        printf("The Centigrade is %.2lf\n", ans);
    }
    else {
        ans = (d * 9 / 5) + 32;
        printf("The Fahrenheit is %.2lf\n", ans);
    }
    return 0;
}

#includeint main()
{
    char op;
    op = getchar();
    if(op>=‘a‘ && op‘z‘)
        op = op - ‘a‘ + ‘A‘;
    else if(op>=‘A‘ && op‘Z‘)
        op = op - ‘A‘ + ‘a‘;
    printf("%c\n", op);
    return 0;
}

#include
#includeint main()
{
    int a, b, c;
    double x1, x2;
    scanf("%d %d %d", &a, &b, &c);
    if(a==0&&b==0)
        printf("Input error!\n");
    else if(a==0){
        x1 = - double(b) / c;
        printf("x=%.6f\n", x1);
    } 
    else {
        double t = b * b - 4 * a * c;
        if(t==0)
            printf("x1=x2=%.6f\n",-double(b)/(2*a));
        else if(t>0){
            x1 = (-b + sqrt(t)) / (2 * a);
            x2 = (-b - sqrt(t)) / (2 * a);
            printf("x1=%.6f\nx2=%.6f\n",x1, x2);
        }  
        else {
            x1 = -double(b) / (2 * a);
            x2 = sqrt(-t) / (2 * a);
            printf("x1=%.6f%+.6fi\n", x1, x2);
            printf("x2=%.6f%+.6fi\n", x1, -x2);
        }
    }
    return 0;
}

#include
#includeint main()
{
    int x, y;
    while(scanf("%d %d", &x, &y)!=EOF) {
        // 分针走的时候 时针也走
        double x_pos = (x%12) * 5  + double(y) / 60.0 * 5;
        // 把整个表分成60份：  (x%12) * 5 -- 时针本来的位置； double(y) / 60.0 * 5 -- 因为分针，时针走的位置 
        double ans = fabs(x_pos - y) 30.0 ? fabs(x_pos - y) : 60.0 - fabs(x_pos - y);
        // 求最小夹角
        printf("At %02d:%02d the angle is %.1lf degrees.\n", x, y, ans * 6.0);
        // ans * 6.0 一份是6度
    }
    return 0;
}