Leetcode.76 Minimum Window Substring (Java)

2021-04-02 16:26

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标签：etc The lex while unique nta imu nim complex

Leetcode.76 Minimum Window Substring

Given a string S and a string T, find the minimum window in S which will contain all the characters in T in complexity O(n).

Example:

Input: S = "ADOBECODEBANC", T = "ABC"
Output: "BANC"

Note:

If there is no such window in S that covers all characters in T, return the empty string "".
If there is such window, you are guaranteed that there will always be only one unique minimum window in S.

Solution

class Solution {
    public String minWindow(String s, String t) {
        int sl = s.length();
        int tl = t.length();
        if(sl == 0 || tl == 0 || sl = 0){
                co ++;
            }
            // 当找到substring需要夹逼找到最短的字串
            if(co == tl){
                while(freq[s.charAt(l)]

Leetcode.76 Minimum Window Substring (Java)

标签：etc The lex while unique nta imu nim complex

原文地址：https://www.cnblogs.com/xm08030623/p/13475945.html

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Leetcode.76 Minimum Window Substring (Java)

Leetcode.76 Minimum Window Substring

Solution

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