C#将RGB图像格式数据转换为BITMAP和BITSOURCE对象
2021-04-07 06:26
标签:get source eth byte can height hand 就是 sys C#将RGB图像格式数据转换为BITMAP和BITSOURCE对象 标签:get source eth byte can height hand 就是 sys 原文地址:https://www.cnblogs.com/cyymfm1314/p/9116193.html
1 public void RGBTOBITMAP(BYTE/*自定义的数据IntPtr*/ bits,int width/*图像的宽度*/,int height/*图像的高度*/)
2 int widthStep = width*3; //一般默认步长为宽度的3倍
3 int lenData = widthStep * height;//数据长度,24位图像数据的长度=宽度*高度*3
4 int len = 0; //代表长度
5 //bits图像帧数据
6 byte[] buffer = new byte[len];//创建指定长度byte数据
7 Marshal.Copy(bits, buffer, 0, buffer.Length);
8
9
10 /*****下面的就是将RGB数据转换为BITMAP对象******/
11 int stride = width * 3;
12 GCHandle handle = GCHandle.Alloc(buffer, GCHandleType.Pinned);
13 int scan0 = (int)handle.AddrOfPinnedObject();
14 scan0 += (height - 1) * stride;
15 System.Drawing.Bitmap bitmap = new System.Drawing.Bitmap(width, height, -stride, System.Drawing.Imaging.PixelFormat.Format24bppRgb, (IntPtr)scan0);
16 handle.Free();
17 /********************************************/
18
19 /*****下面的代码是显示到wpf的Image控件上实时显示******/
20 IntPtr ip = bitmap.GetHbitmap();//从GDI+ Bitmap创建GDI位图对象
21
22 BitmapSource bitmapSource = System.Windows.Interop.Imaging.CreateBitmapSourceFromHBitmap(ip, IntPtr.Zero, Int32Rect.Empty,
23 System.Windows.Media.Imaging.BitmapSizeOptions.FromEmptyOptions());
24
25 image1.Source = bitmapSource;
26 /********************************************/
27 bitmap.Dispose(); //bitmap释放
28
29 /*使用DeleteObejct这个函数需要从gdi32.dll导入函数
30 [System.Runtime.InteropServices.DllImport("gdi32.dll")]
31 public static extern bool DeleteObject(IntPtr hObject);*/
32 DeleteObject(ip);
文章标题:C#将RGB图像格式数据转换为BITMAP和BITSOURCE对象
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