C#比较两个list集合,两集合同时存在或A集合存在B集合中无
标签:实现 sub stat 集合 cti contains list sum lin
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading;
using System.Threading.Tasks;
namespace Sample3
{
class Program
{
static void Main(string[] args)
{
var student1 = new List();
student1.Add(new student() { name = "张三", subject = "英语", score = 89 });
student1.Add(new student() { name = "李四", subject = "英语", score = 95 });
student1.Add(new student() { name = "王五", subject = "英语", score = 69 });
student1.Add(new student() { name = "李倩", subject = "英语", score = 99 });
var student2 = new List();
student2.Add(new student() { name = "李四", subject = "英语", score = 95 });
student2.Add(new student() { name = "王五", subject = "数学", score = 69 });
student2.Add(new student() { name = "赵六", subject = "数学", score = 100 });
//var exp1 = student1.Where(a => student2.Any(t => a.name.Contains(t.name))).ToList();
//使用Exists同样可以实现 字面上应该更好理解,而且效率要高些
var exp1 = student1.Where(a => student2.Exists(t => a.name.Contains(t.name))).ToList();
Console.WriteLine("--查找student1和student2总同时存在的数据--");
foreach (var item in exp1)
{
Console.WriteLine("{0} \t {1} \t {2}", item.name, item.subject, item.score);
}
//var exp2 = student1.Where(a => student2.All(t => !a.name.Contains(t.name))).ToList();
//使用Exists同样可以实现 字面上应该更好理解,而且效率要高些
var exp2 = student1.Where(a => !student2.Exists(t => a.name.Contains(t.name))).ToList();
Console.WriteLine("--查找student1集合中存在,而student2不存在的数据--");
foreach (var item in exp2)
{
Console.WriteLine("{0} \t {1} \t {2}", item.name, item.subject, item.score);
}
Console.Read();
/*
--查找student1和student2总同时存在的数据--
李四 英语 95
王五 英语 69
--查找student1集合中存在,而student2不存在的数据--
张三 英语 89
李倩 英语 99
*/
}
}
public class student
{
///
/// 姓名
///
public string name;
///
/// 科目
///
public string subject;
///
/// 分数
///
public int score;
}
}
C#比较两个list集合,两集合同时存在或A集合存在B集合中无
标签:实现 sub stat 集合 cti contains list sum lin
原文地址:http://www.cnblogs.com/smartsmile/p/7675572.html
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