C#比较两个list集合,两集合同时存在或A集合存在B集合中无

2021-05-05 21:29

阅读:635

标签:实现   sub   stat   集合   cti   contains   list   sum   lin   

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading;
using System.Threading.Tasks;

namespace Sample3
{
    class Program
    {
        static void Main(string[] args)
        {
            var student1 = new List();
            student1.Add(new student() { name = "张三", subject = "英语", score = 89 });
            student1.Add(new student() { name = "李四", subject = "英语", score = 95 });
            student1.Add(new student() { name = "王五", subject = "英语", score = 69 });
            student1.Add(new student() { name = "李倩", subject = "英语", score = 99 });

            var student2 = new List();
            student2.Add(new student() { name = "李四", subject = "英语", score = 95 });
            student2.Add(new student() { name = "王五", subject = "数学", score = 69 });
            student2.Add(new student() { name = "赵六", subject = "数学", score = 100 });

            //var exp1 = student1.Where(a => student2.Any(t => a.name.Contains(t.name))).ToList();
            //使用Exists同样可以实现 字面上应该更好理解,而且效率要高些
            var exp1 = student1.Where(a => student2.Exists(t => a.name.Contains(t.name))).ToList();
            Console.WriteLine("--查找student1和student2总同时存在的数据--");
            foreach (var item in exp1)
            {
                Console.WriteLine("{0} \t {1} \t {2}", item.name, item.subject, item.score);
            }

            //var exp2 = student1.Where(a => student2.All(t => !a.name.Contains(t.name))).ToList();  
            //使用Exists同样可以实现 字面上应该更好理解,而且效率要高些
            var exp2 = student1.Where(a => !student2.Exists(t => a.name.Contains(t.name))).ToList();
            Console.WriteLine("--查找student1集合中存在,而student2不存在的数据--");
            foreach (var item in exp2)
            {
                Console.WriteLine("{0} \t {1} \t {2}", item.name, item.subject, item.score);
            }
            Console.Read();

            /*
                --查找student1和student2总同时存在的数据--
                李四     英语    95
                王五     英语    69
                --查找student1集合中存在,而student2不存在的数据--
                张三     英语    89
                李倩     英语    99 
             */
        }
    }

    public class student
    {
        ///   
        /// 姓名  
        ///   
        public string name;
        ///   
        /// 科目  
        ///   
        public string subject;
        ///   
        /// 分数  
        ///   
        public int score;
    }  
}

 

C#比较两个list集合,两集合同时存在或A集合存在B集合中无

标签:实现   sub   stat   集合   cti   contains   list   sum   lin   

原文地址:http://www.cnblogs.com/smartsmile/p/7675572.html


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