[LeetCode&Python] Problem 617. Merge Two Binary Trees
2021-05-16 00:30
标签：and python output for tar lse start use out Given two binary trees and imagine that when you put one of them to cover the other, some nodes of the two trees are overlapped while the others are not. You need to merge them into a new binary tree. The merge rule is that if two nodes overlap, then sum node values up as the new value of the merged node. Otherwise, the NOT null node will be used as the node of new tree. Example 1: Note: The merging process must start from the root nodes of both trees. [LeetCode&Python] Problem 617. Merge Two Binary Trees 标签：and python output for tar lse start use out 原文地址：https://www.cnblogs.com/chiyeung/p/9749943.htmlInput:
Tree 1 Tree 2
1 2
/ \ / \
3 2 1 3
/ \ \
5 4 7
Output:
Merged tree:
3
/ 4 5
/ \ \
5 4 7
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def mergeTrees(self, t1, t2):
"""
:type t1: TreeNode
:type t2: TreeNode
:rtype: TreeNode
"""
if t1==None and t2!=None:
return t2
elif t1!=None and t2==None:
return t1
elif t1==None and t2==None:
return None
else:
def submergetree(r1,r2):
if r1!=None and r2==None:
return r1
elif r1==None and r2!=None:
return r2
elif r1==None and r2==None:
return None
else:
r1.val+=r2.val
r1.left=submergetree(r1.left,r2.left)
r1.right=submergetree(r1.right,r2.right)
return r1
return submergetree(t1,t2)
文章标题：[LeetCode&Python] Problem 617. Merge Two Binary Trees
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