【HDOJ6222】Heron and His Triangle(Java,二分,递推)
2021-05-17 06:29
标签:直接 ring com rgs heron str ++ e30 一个 题意:让你找这样的一个三角形,三条边为t,t-1,t+1,并且面积为整数,最后满足t大于等于n。 n
思路:直接推式子不会,打表找规律 f(n)=4*f(n-1)-f(n-2)(n>=3) f(1)=4 f(2)=14 队友用Java写的,再写个二分就行 【HDOJ6222】Heron and His Triangle(Java,二分,递推) 标签:直接 ring com rgs heron str ++ e30 一个 原文地址:https://www.cnblogs.com/myx12345/p/9747511.html 1 import java.math.BigInteger;
2 import java.util.Arrays;
3 import java.util.Scanner;
4
5
6 public class Main {
7 public static void main(String[] args){
8 int t;
9 BigInteger[] a = new BigInteger[110];
10 BigInteger n;
11 Scanner sc = new Scanner(System.in);
12 //System.out.println(new BigInteger("11").compareTo(new BigInteger("9")));
13 a[1] = new BigInteger("4");
14 a[2] = new BigInteger("14");
15 a[3] = new BigInteger("52");
16 for(int j = 4; j j){
17 a[j] = a[j - 1].multiply(new BigInteger("4")).subtract(a[j - 2]);
18 }
19 t = sc.nextInt();
20 for(int i = 1; i i){
21 n = sc.nextBigInteger();
22 //System.out.println(n);
23 for(int j = 1; j j){
24 if(a[j].compareTo(n) >= 0){
25 System.out.println(a[j]);
26 break;
27 }
28 }
29 }
30 }
文章标题:【HDOJ6222】Heron and His Triangle(Java,二分,递推)
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