实验1 C语言开发环境使用和数据类型、运算符、表达式
标签:ima oat getc 选择 字符 解决 load amp info
//打印一个字符小人
#include int main() {
printf(" o \n");
printf("\n");
printf("I I\n");
printf(" o \n");
printf("\n");
printf("I I\n");
return 0;
}
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//打印一个字符小人
#include int main() {
printf(" o o\n");
printf("\n");
printf("I I I I\n");
return 0;
}
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/* 用C语言实现一个简单的算术运算程序 */
#include int main() {
int x, y; //定义两个整型变量,用来保存运算数据
int r1, r2, r3, r4; //定义四个整型变量,用来保存加减乘除运算结果
x = 1;
y = 2;
r1 = x + y;
r2 = x - y;
r3 = x * y;
r4 = x / y;
printf("r1 = %d\n", r1);
printf("r2 = %d\n", r2);
printf("r3 = %d\n", r3);
printf("r4 = %d\n", r4);
return 0;
}
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/* 用C语言实现一个简单的算术运算程序 */
#include int main() {
float x, y; //定义两个整型变量,用来保存运算数据
float r1, r2, r3, r4; //定义四个整型变量,用来保存加减乘除运算结果
x = 1;
y = 2;
r1 = x + y;
r2 = x - y;
r3 = x * y;
r4 = x / y;
printf("r1 = %f\n", r1);
printf("r2 = %f\n", r2);
printf("r3 = %f\n", r3);
printf("r4 = %f\n", r4);
return 0;
}
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#include int main() {
int n, r1, r2, r3, r4;
n = 100;
r1 = n*(n+1)/2;
r2 = (n+1)*n/2;
r3 = n/2*(n+1);
r4 = (n+1)/2*n;
printf("n = %d\n", n);
printf("r1 = %d\n", r1);
printf("r2 = %d\n", r2);
printf("r3 = %d\n", r3);
printf("r4 = %d\n", r4);
return 0;
}
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#include int main() {
int n, r1, r2, r3, r4;
n = 101;
r1 = n*(n+1)/2;
r2 = (n+1)*n/2;
r3 = n/2*(n+1);
r4 = (n+1)/2*n;
printf("n = %d\n", n);
printf("r1 = %d\n", r1);
printf("r2 = %d\n", r2);
printf("r3 = %d\n", r3);
printf("r4 = %d\n", r4);
return 0;
}
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#include int main() {
int answer;
char words[5000];
printf("网课学习让一些人欢喜一些人忧.\n");
printf("1. 作为一个宅,社恐,觉得这样很好。有网络,自主学习,很ok.\n");
printf("2. 不喜,不喜,很不喜。眼睛快瞎了。脑壳有点卡...\n");
printf("3. 中间派。不知道。说不清。\n");
printf("4. 其它...\n");
printf("你的选择: ");
scanf("%d", &answer);
if(answer == 4) {
printf("请补充说明你的想法: \n");
getchar();
gets(words);
}
printf("\n");
printf("当遇到问题时,你会选择:\n");
printf("1. 遇到问题,就解决问题。不懂的,搜索式学习,逐个攻破.\n");
printf("2. 遇到问题,不高兴。然后,...,没有了.\n");
printf("3. 其它...\n");
printf("你的选择: ");
scanf("%d", &answer);
if(answer == 1)
printf(":)\n");
else if(answer == 2)
printf("这样不能解决问题啊...我们选择1好不好:)\n");
else if(answer == 3) {
printf("请补充说明你的想法: \n");
getchar();
gets(words);
}
return 0;
}
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#include int main() {
int answer;
char words[5000];
printf("现在的天气让人感觉很头疼.\n");
printf("1. 作为一个南方人觉得这样很好。湿润,温和,很ok.\n");
printf("2. 不喜,不喜,很不喜潮湿。北方人向往干燥...\n");
printf("3. 中间派。不知道。说不清。\n");
printf("4. 其它...\n");
printf("你的选择: ");
scanf("%d", &answer);
if(answer == 4) {
printf("请补充说明你的想法: \n");
getchar();
gets(words);
}
printf("\n");
printf("当突然降温时,你会选择:\n");
printf("1. 小问题,不用穿很厚.\n");
printf("2. 翻出衣柜里的毛衣和秋裤.\n");
printf("3. 其它...\n");
printf("你的选择: ");
scanf("%d", &answer);
if(answer == 1)
printf("真真真硬汉:)\n");
else if(answer == 2)
printf(":)\n");
else if(answer == 3) {
printf("请补充说明你的想法: \n");
getchar();
gets(words);
}
return 0;
}
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实验1 C语言开发环境使用和数据类型、运算符、表达式
标签:ima oat getc 选择 字符 解决 load amp info
原文地址:https://www.cnblogs.com/chenruiyu0167/p/14542534.html
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