java基于Hash表和双向链表简单实现LRU Cache

2021-06-27 23:07

阅读:657

标签:cap   lru   实现   public   int   port   class   头结点   void   

package lru;

import java.util.HashMap;

public class LRUCache2 {
    public final int capacity;
    class DNode{
        K key;
        V value;
        DNode next;
        DNode pre;
        public DNode(K key, V value, LRUCache2.DNode pre, LRUCache2.DNode next) {
            super();
            this.key = key;
            this.value = value;
            this.pre = pre;
            this.next = next;
        }
        
    }
    
  //附加头结点 DNode head
=new DNode(null,null,null,null); DNode last=head; HashMap map=new HashMap(); public LRUCache2(int capacity) { this.capacity=capacity; } public V get(K key) { DNode node=map.get(key); if(node!=null) { moveToHead(node); } return node==null?null:node.value; } public void put(K key, V value) { DNode node=map.get(key); if(node==null) { if(map.size()>=capacity) { removeLast(); } node=new DNode(key, value,head,head.next); if(head.next!=null) head.next.pre=node; head.next=node; map.put(node.key, node); if(last==head) last=node; }else { node.value=value; moveToHead(node); } } private void removeLast() { // TODO Auto-generated method stub if(last==null) { throw new IllegalArgumentException("cant remove before put"); } map.remove(last.key); last.pre.next=null; last=last.pre; } private void moveToHead(LRUCache2.DNode node) { // TODO Auto-generated method stub if(head.next==node) return; if(last==node) { last=node.pre; } node.pre.next=node.next; if(node.next!=null) node.next.pre=node.pre; node.next=head.next; node.pre=head; head.next.pre=node; head.next=node; } }

 

java基于Hash表和双向链表简单实现LRU Cache

标签:cap   lru   实现   public   int   port   class   头结点   void   

原文地址:https://www.cnblogs.com/lshao/p/9650673.html


评论


亲,登录后才可以留言!