C# 后台获取前台交互判断
2021-06-29 19:05
标签：获取 int new rgs tor code var lse ati 前台传来明细 ，判断是否修改，在把前台 的数据组成新的类保存 C# 后台获取前台交互判断 标签：获取 int new rgs tor code var lse ati 原文地址：https://www.cnblogs.com/LiuFengH/p/10005862.html 1 public class tt
2 {
3 public string id { get; set; }
4 public string e_id { get; set; }
5 public string name { get; set; }
6 public int age { get; set; }
7 public bool sex { get; set; }
8
9 }
10 public class t
11 {
12 public string id { get; set; }
13 public string name { get; set; }
14 public List dd { get; set; }
15 }
16 class Program
17 {
18
19 static void Main(string[] args)
20 {
21 var q = new List { new tt { id = "123",e_id="1", name = "pg", age = 12, sex = true }, new tt { id = "124",e_id="1", name = "pp", age = 13, sex = true } }; //后台数据
22 var w = new List { new tt { name = "pg", e_id = "2", age = 12, sex = true }, new ConsoleApplication2.tt { name = "pp", e_id = "2", age = 13, sex = true }, new tt { name = "ppd", e_id = "2", age = 11, sex = true } }; //前台数据
23
24 var e = new t { id = "1", name = "pg", dd = q }; //父行
25
26 var ischange1 = false;
27 var ischange2 = false;
28 foreach (var item in w)
29 {
30 item.e_id = e.id; //父ID
31 tt ex = q.Where(d => d.name == item.name).FirstOrDefault();
32 if (ex == null)
33 {
34 ischange2 = true;
35 }
36 else
37 {
38 if (ex.age != item.age || ex.sex != item.sex)
39 {
40 ischange2 = true;
41 }
42 }
43 }
44
45 if (q.Count != w.Count)
46 {
47 ischange2 = true;
48 }
49 if (ischange1 == true || ischange2 == true)
50 {
51 if (ischange2 == true)
52 {
53 e.dd = w;
54 }
55 }
56 Console.WriteLine(ischange2);
57
58 Console.ReadKey(true);
59 }
60
61 }