C#实现农历日历的方法

private  static string []TianGan =   {“甲”,”乙”,”丙”,”丁”,”戊”,”己”,”庚”,”辛”,”壬”,”癸”};

//地支

private  static string []DiZhi =     {“子”,”丑”,”寅”,”卯”,”辰”,”巳”,”午”,”未”,”申”,”酉”,”戌”,”亥”};

//十二生肖

private  static string []ShengXiao = {“鼠”,”牛”,”虎”,”兔”,”龙”,”蛇”,”马”,”羊”,”猴”,”鸡”,”狗”,”猪”};

//农历日期

private  static string []DayName =   {“*”,”初一”,”初二”,”初三”,”初四”,”初五”,”初六”,”初七”,”初八”,”初九”,”初十”,  “十一”,”十二”,”十三”,”十四”,”十五”,             “十六”,”十七”,”十八”,”十九”,”二十”,             “廿一”,”廿二”,”廿三”,”廿四”,”廿五”,                   “廿六”,”廿七”,”廿八”,”廿九”,”三十”};

//农历月份

private static string []MonthName =  {“*”,”正”,”二”,”三”,”四”,”五”,”六”,”七”,”八”,”九”,”十”,”十一”,”腊”};

//公历月计数天

private  static int []MonthAdd =      {0,31,59,90,120,151,181,212,243,273,304,334};

//农历数据

private static int []LunarData =    {2635,333387,1701,1748,267701,694,2391,133423,1175,396438            ,3402,3749,331177,1453,694,201326,2350,465197,3221,3402            ,400202,2901,1386,267611,605,2349,137515,2709,464533,1738            ,2901,330421,1242,2651,199255,1323,529706,3733,1706,398762            ,2741,1206,267438,2647,1318,204070,3477,461653,1386,2413            ,330077,1197,2637,268877,3365,531109,2900,2922,398042,2395            ,1179,267415,2635,661067,1701,1748,398772,2742,2391,330031            ,1175,1611,200010,3749,527717,1452,2742,332397,2350,3222            ,268949,3402,3493,133973,1386,464219,605,2349,334123,2709            ,2890,267946,2773,592565,1210,2651,395863,1323,2707,265877};

///

/// 获取对应日期的农历

///

///

/// 公历日期

///

///

public string GetLunarCalendar(DateTime dtDay)

{

string sYear = dtDay.Year.ToString(); string sMonth = dtDay.Month.ToString();

string sDay = dtDay.Day.ToString();

int year;

int month;

int day;

try {

year = int.Parse(sYear);

month = int.Parse(sMonth);

day = int.Parse(sDay);

}

catch {

year = DateTime.Now.Year;

month = DateTime.Now.Month;

day = DateTime.Now.Day;

}

int nTheDate;

int nIsEnd;

int k, m, n, nBit, i;

string calendar = string.Empty;

//计算到初始时间1921年2月8日的天数：1921-2-8(正月初一)

nTheDate = (year – 1921) * 365 + (year – 1921) / 4 + day + MonthAdd[month – 1] – 38;

if ((year % 4 == 0) && (month > 2)) nTheDate += 1;

//计算天干，地支，月，日

nIsEnd = 0; m = 0; k = 0; n = 0;

while (nIsEnd != 1)

{

if (LunarData[m] = 0)

{     //获取LunarData[m]的第n个二进制位的值

nBit = LunarData[m];

for (i = 1; i

nBit = nBit % 2;

if (nTheDate

nTheDate = nTheDate – 29 – nBit; n = n – 1;

}

if (nIsEnd == 1) break; m = m + 1;

}

year = 1921 + m; month = k – n + 1; day = nTheDate;