求立方体的体积、表面积(c++)

2020-12-13 04:26

阅读:618

标签:功能   没有   system   double   使用   构造   inpu   sys   efault   

//求立方体的体积、表面积(c++)

#include
#include
#define COST 20
using namespace std;

class tiji
{
private:
double length,width,height;
public:
tiji(){};
tiji(double l, double w, double h) //构造函数的形参,给私有变量赋值
{
length =l;
width =w;
height =h;
}
double changft_tiji()
{
//double v;
double v=length*width*height;
return v;
}
double biao_area()
{
double s;
s=2*(length*height+length*width+width*height);
return s;
}
double repaie()
{
double ss ;
ss = 2*(length*height+length*width+width*height)-length*width;
return ss;
}

void input(); //声明

};

void tiji::input()
{
cin>>length>>width>>height;
}

void menu()
{
cout cout cout cout cout cout}
void _exit()
{
cout cout cout cout cout}


int main ()
{
tiji B;
int c;
menu();
while(1)
{
cout B.input();
cout cin>>c;
switch(c)
{
case 1:
cout break;
case 2:
cout break;
case 3:
cout break;
case 0:
system("cls");//清屏
_exit();
exit(1);
break;
default:
cout }
}


//B.changft_tiji(3,4,5)
//cout //cout //cout return 1;//1 代表真
}




求立方体的体积、表面积(c++)

标签:功能   没有   system   double   使用   构造   inpu   sys   efault   

原文地址:https://www.cnblogs.com/duanqibo/p/11110323.html


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