python thread 并发且顺序运行示例
2018-10-15 17:35
复制代码 代码如下:
#-*- coding:utf-8 -*-
import threading
import time
def fun(name, ls_name, front_thread = None):
线程启动函数
通过front_thread来使用线程有序的运行
time.clock()
time.sleep(2)
# 如果front_thread存在，则在front_thread运行完成后，才运行当前线程
if front_thread != None:
front_thread.join()
ls_name.append(name)
print thread %s : %s% (name, time.clock())
if __name__ == __main__:
ls_result_name = []
ls_thread = []
time.clock()
# 逐一启动1000个线程
for i in range(0,10):
if len(ls_thread) == 0:
t = threading.Thread(target=fun, args=(i,ls_result_name,None))
else:
t = threading.Thread(target=fun, args=(i,ls_result_name,ls_thread[-1]))
t.start()
ls_thread.append(t)
# 等待所有线程结束
for t in ls_thread:
t.join()
print ls_result_name:, ls_result_name
print main thread:%s % time.clock()
运行结果为：
thread 0 : 1.99962006344
thread 1 : 2.00000866032
thread 2 : 2.00059113658
thread 3 : 2.00080345407
thread 4 : 2.00100068584
thread 5 : 2.00119456523
thread 6 : 2.00138593033
thread 7 : 2.00166753037
thread 8 : 2.00211758757
thread 9 : 2.0024776892
ls_result_name: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
main thread:2.003211302
线程更明细的使用可参考：
time.clock模块的更详细介绍可参考：
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